Find the smallest number which leaves a remainder of 5 when divided by 24,32 and 42. Find the smallest Question Find the smallest number which leaves a remainder of 5 when divided by 24,32 and 42.Find the smallest in progress 0 Math Adalyn 4 days 2021-10-11T05:48:21+00:00 2021-10-11T05:48:21+00:00 2 Answers 0 views 0

## Answers ( )

Step-by-step explanation:WhensmallernumberweshoulddoLCMbutiflargernumberweshoulddoHCF.IhopeithelpsyouAnswer:677Step-by-step explanation:Let the number be ‘N’.

Now N, when divided by 24, 32 & 42 leaves remainder 5.

In other words, (N-5) will be complely divisible by 24, 32 and 42 and the least as well.

So, (N-5) has to be the LCM of 24, 32 & 42.

LCM (24, 32, 42) = 672 = (N-5)

So, N = 677 (Answer)

Note: In general, if we have multiple Divisors giving the same Remainder, then the number is given as:

[N = LCM of Divisors + Remainder]

Hope this helps u.

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